How can I change ca(hco3)2+cl(aq)=cacl2(aq)

  1. How can I change ca(hco3)2+cl(aq)=cacl2(aq) + co2(g) + h2O in to ironic equation?
    1. answers icon 1 answer
    2. marcellino asked by marcellino
    3. views icon 480 views
  2. Write out the Ka and Kb for the biocarbonate ion with chemical equation:Would this be correct: HCO3^-(aq) <--> H+(aq) +
    1. answers icon 1 answer
    2. Saira asked by Saira
    3. views icon 986 views
  3. How mush CaCl2, in grams, is needed to make 2.0 L of a 3.5M solution?g CaCl2 = (2.0L) *( 3.5 mol Cl-/1L) * (1mol CaCl2/ 2mol
    1. answers icon 1 answer
    2. Sydney asked by Sydney
    3. views icon 2,892 views
  4. Write the ionic equation for these reaction.Ca(HCO3)2 + HCL = CaCl2 + CO2 + H2O ZnO + HNO3 = Zn(NO3)2 + H2O
    1. answers icon 1 answer
    2. James asked by James
    3. views icon 1,509 views
  5. If 2.1 moles of CaCl2 are dissolved in enough water to make a 0.92-liter solution, what is the resulting molarity?0.44 M CaCl2
    1. answers icon 3 answers
    2. smith asked by smith
    3. views icon 2,074 views
  6. ChemistryBicarbonate is an ion with the chemical formula HCO3–. In the presence of water, it results in the following
    1. answers icon 1 answer
    2. views icon 100 views
  7. ChemistryBicarbonate is an ion with the chemical formula HCO3–. In the presence of water, it results in the following
    1. answers icon 3 answers
    2. views icon 108 views
  8. How can we calculate the HCO3- (bicarbonate ion) concentration in water in 25C pH7.0?I think we can use PV=nRT equation, but I
    1. answers icon 0 answers
    2. Anonymous asked by Anonymous
    3. views icon 542 views
  9. Determne the boiling point of 16.3g of calcium chloride dissolved in 250. g water.My work: 16.3 g CaCl2 *(1 mole CaCl2/110.984 g
    1. answers icon 1 answer
    2. Julia asked by Julia
    3. views icon 870 views
  10. Ca(HCO3)2(s) decomposes at elevated temperatures according to the stoichiometric equation Ca(HCO3)2(s)-> CaCO3(s) + H2O(g) +
    1. answers icon 1 answer
    2. Jill asked by Jill
    3. views icon 2,047 views