H3PO4 + 3KOH = K3PO4

  1. Determine the starting mass of each reactant if 46.3 of K3PO4 is produced and 92.8 of H3PO4 remains unreacted.3KOH + H3PO4 ---->
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    2. Anonymous asked by Anonymous
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  2. Determine the starting mass of each reactant if 46.3 of K3PO4 is produced and 92.8 of H3PO4 remains unreacted.3KOH + H3PO4 ---->
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    2. Anonymous asked by Anonymous
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  3. The neutralization of H3PO4 with KOH is exothermic.H3PO4(aq) + 3KOH(aq) -> 3H2O(l) +K3PO4(aq) +173.2KJ 70.0 mL of 0.207 M H3PO4
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    2. Sally asked by Sally
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  4. what was the concentration of the unknown h3po4 solution h3po4(aq)+3koh(aq)→3h2o(l)+k3po4(aq)
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    2. chris asked by chris
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  5. a 10.0mL sample of an unknown H3PO4 solution requirs 112mL of 0.100 M KOH to completely react with the H3PO4. What was the
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    2. Monique asked by Monique
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  6. A 11.0-mL sample of an unknown H3PO4 solution requires 116mL of 0.140 KOH to completely react with the H3PO4.What was the
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    2. April asked by April
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  7. H3PO4 + 3KOH = K3PO4 + 3 H2O What would be the percent yield if you reacted 49.0g of H3PO4 with 112g of potassium hydroxide, and
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    2. Glenda asked by Glenda
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  8. H3PO4 + 3KOH = K3PO4 + 3 H2O What would be the percent yield if you reacted 49.0g of H3PO4 with 112g of potassium hydroxide, and
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    2. andi asked by andi
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  9. A solution of 0.314M KOH is used to neutralize 10.0mL H3PO4 solution.H3PO4(aq) + 3KOH(aq) → K3PO4(aq) + 3H2O(l) If 29.3mL KOH
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    2. ellie asked by ellie
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  10. A solution of 0.314M KOH is used to neutralize 10.0mL H3PO4 solution.H3PO4(aq) + 3KOH(aq) → K3PO4(aq) + 3H2O(l) If 29.3mL KOH
    1. answers icon 1 answer
    2. ellie asked by ellie
    3. views icon 674 views