Find the d^3z/dydx^2 partial derivative

Find the d^3z/dydx^2 partial derivative of:ln[sin(x-y)] The answer is supposed to be 1/2; however, I cannot figure out how to
1. 2 answers
2. asked by James
3. 511 views
Please check my answers and let me know if I did something wrong. Thank you!Find the partial derivative of x, and the partial
1. 1 answer
2. asked by Jennifer
3. 757 views
Find dy/dx if y=csc(2x−−√) . (1 point) Responses dydx=−csc(2x√)cot(2x√)x√ d y d x = − csc ( 2 x ) cot ( 2 x ) x
1. 1 answer
2. 134 views
Evaluate: f(x,y)=2x^3e^ya) partial derivative with respect to x. I know that you have to treat y as a constant but I have no
1. 2 answers
2. asked by Hannah
3. 701 views
Find d VC/ d y = ((y/240)^2)(w)= 2yw/240^2 + 0 + y^2/240^2 but final answer is.... = 2yw/240^2 So, is the question asking for
1. 1 answer
2. asked by Anonymous
3. 1,214 views
Find dydx if y=csc3x+1−−−−−√ . (1 point) Responses dydx=−3csc3x+1√ ⋅ cot3x+1√3x+1√ d y d x = − 3 csc 3 x
1. 1 answer
2. 77 views
Find dy/dx if y=sinx⋅sin−1x . (1 point) Responses dydx=cosx ⋅ sin−1x+sinx1+x2 d y d x = cos x · sin − 1 x + sin x 1 +
1. 1 answer
2. 104 views
Find out the partial derivative w.r.t 'x' and 'y' off (x,y) = log(y) x Now, log(y) x = ln x / ln y Partial Diff w.r.t 'x' = 1/ x
1. 1 answer
2. asked by Akki
3. 1,692 views
z=u(v+w)^(1/2) find ∂^3z/(∂u∂v∂w)what partial derivative am I suppose to be finding exactly? Do I take the derivative of
1. 0 answers
2. asked by C
3. 576 views
Prove that (grad)^2 f(r) = D^2/dr^2 + (2/r) Df/DrWhere D^2/dr^2 refers to the second partial derivative of f , w.r.t. r and Df/
1. 0 answers
2. asked by Aryaa
3. 708 views