Question

Find dy/dx if y=csc(2x−−√) . (1 point) Responses dydx=−csc(2x√)cot(2x√)x√ d y d x = − csc ( 2 x ) cot ( 2 x ) x dydx=csc(2x√)cot(2x√)x√ d y d x = csc ( 2 x ) cot ( 2 x ) x dydx=−2csc(2x√)cot(2x√)x√ d y d x = − 2 csc ( 2 x ) cot ( 2 x ) x dydx=2csc(2x√)cot(2x√)x√ d y d x = 2 csc ( 2 x ) cot ( 2 x ) x dydx=−csc(2x√)cot(2x√)2x√

Answer 1

The correct response is:

dy/dx = -2csc(2x√)cot(2x√)√