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Evaluate the integral. ∫arctan(√x) dx
also:
integral of tan^(-1)y dy how is integration of parts used in that? You write: arctan(y)dy = d[y arctan(y)] - y d[arctan(y)]
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asked by
marsha
722 views
h(x)= integral from (1, 1/x) arctan(2t)dt
part 1: let U= 1/x and du= ? -> using u=1/x, we can write h(x)= integral from (1, 1/x)
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asked by
Anonymous
605 views
h(x)= integral from (1, 1/x) arctan(2t)dt
part 1: let U= 1/x and du= ? -> using u=1/x, we can write h(x)= integral from (1, 1/x)
0 answers
asked by
Anonymous
967 views
Evaluate the integral (3x+4)/[(x^2+4)(3-x)]dx
a. (1/2)ln(x^2+4) + ln|3-x| + C b. (1/2)arctan(x/2) + ln|3-x| + C c.
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asked by
Darren
463 views
Evaluate the integral. ∫arctan(√x) dx
2 answers
asked by
A
592 views
Find the integral from -∞ to -1 of 1/(1+x²) dx.
I started working the problem out, and so far I got the lim as z→-∞ of
1 answer
asked by
Erica
608 views
Use the integral identity:
∫(a-1) (1/(1+x^2))dx=∫(1-1/a) (1/(1+u^2))du for a>1 to show that: arctan(a)+arctan(1/a)=π/2
1 answer
asked by
Andre
523 views
The values of x that are solutions to the equation cos^(2)x=sin2x in the interval [0, pi] are
a. arctan(1/2) only b. arctan(1/2)
1 answer
asked by
Carson
706 views
Note that
pi lim arctan(x ) = ---- x -> +oo 2 Now evaluate / pi \ lim |arctan(x ) - -----| x x -> +oo \ 2 / I'm not exactly sure
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asked by
Frederique
919 views
Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if it is convergent or divergent).
I know how to find the
2 answers
asked by
Sam
752 views