Equation: Fe2O3 + 2Al --->

  1. For the following reaction:Fe2O3 + 3CO --> 2Fe + 3CO2 how many grams of Fe2O3 is needed to produce 111 g of Fe? A) 79.3 g Fe2O3
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    2. Petey asked by Petey
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  2. Equation: Fe2O3 + 2Al ---> 2Fe + Al2O3.How many grams of Fe2O3 react with excess Al to make 475g Fe? Can you show me step by
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    2. Anan asked by Anan
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  3. Calculate the number of grams of Fe formed when 0.300kg of Fe2O3 reacts.Equation: Fe2O3+CO-->Fe+CO2 converted .300kg to 300g
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    2. Ezra asked by Ezra
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  4. QuestionGiven the equation: 4 Fe(s) + 3 O2(g) ? 2 Fe2O3(s), what is the theoretical yield of Fe2O3 from the reaction of 4.86 g
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    2. Kami asked by Kami
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  5. 0.250g of Fe3O4 reacts with excess O2 to give Fe2O3 in 73.2% yield according to the following balanced equation:
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  6. 0.300g of Fe3O4 reacts with excess O2 to give Fe2O3 in 61.1% yield according to the following balanced equation:
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  7. 37.5 g of Fe2O3 is added to 240 cm^3 of HCl. The reaction occurs according to equation : 6HCl + Fe2O3 -> 2FeCl + 3H2OAt the end
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    2. Lilo asked by Lilo
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  8. Please tell me what I did wrong on this problem:Given the equation Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g), Calculate the number of
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    2. Theresa asked by Theresa
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  9. How many particles are in 9.22 x 10^–37 mol of iron(III) oxide (Fe2O3)?A. 5.54 x 10^12 mol Fe2O3 B. 1.60 x 10^23 mol Fe2O3 C.
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    2. Michael asked by Michael
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  10. How many particles are in 9.22 x 10–37 mol of iron(III) oxide (Fe2O3)?5.55 * 10^-13 mol Fe2O3 5.54 * 10^12 mol Fe2O3 1.47 *
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    2. Summer asked by Summer
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