Question
How many particles are in 9.22 x 10–37 mol of iron(III) oxide (Fe2O3)?
5.55 * 10^-13 mol Fe2O3
5.54 * 10^12 mol Fe2O3
1.47 * 10^-23 mol Fe2O3
1.60 * 10^23 mol Fe2O3
5.55 * 10^-13 mol Fe2O3
5.54 * 10^12 mol Fe2O3
1.47 * 10^-23 mol Fe2O3
1.60 * 10^23 mol Fe2O3
Answers
DrBob222
1 mol of anything contains 6.022E23 particles of whatever those things are; i.e.,
1 mol x (6.022E23 particles/mol) = ?
2 mol x (6.022E23 particles/mol) = ?
etc.
Post your work if you still don't get it.
1 mol x (6.022E23 particles/mol) = ?
2 mol x (6.022E23 particles/mol) = ?
etc.
Post your work if you still don't get it.