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Consider the following equilibrium: PCl5

PCl5 dissociates according to the reaction: PCl5(g) ↔ PCl3(g) + Cl2(g). One mole of PCl5 was placed in one liter of solution.
1. 2 answers
2. asked by Sam
3. 3,414 views
For the following reaction at 600. K, the equilibrium constant, Kp is 11.5.PCl5(g) PCl3(g) + Cl2(g) Suppose that 3.314 g of PCl5
1. 1 answer
2. asked by Anonymous
3. 1,192 views
For the following reaction at 600. K, the equilibrium constant, Kp, is 11.5.PCl5(g) = PCl3(g) + Cl2(g) Suppose that 2.510 g of
1. 2 answers
2. asked by Writeacher
3. 3,017 views
At a certain temperature, .5 mol of PCl5 was placed in a .25 L vessel and permitted to react as shownPCl5 (g) --> PCl3 (g)+ Cl2
1. 1 answer
2. asked by Alex
3. 641 views
At a certain temperature, 2.00 moles of phosphorus(V) chloride, PCl5, was placed in a 1.0 L vessel and permitted to react as
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2. asked by chem
3. 594 views
If the equilibrium concentrations are [PCl5] = 1.0M, [Cl2] = 0.10M, what is the equilibrium constant value?PCl5(g) <---> PCl3(g)
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2. asked by Cathy
3. 2,718 views
The decomposition reaction for PCl5 for which the equilibrium constant is 0.030. If you begin an experiment with 0.040M PCl5.
1. 3 answers
2. asked by Kathy
3. 1,336 views
The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K:PCl5(g) PCl3(g) + Cl2(g) Calculate the equilibrium
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2. asked by Kayla23
3. 2,297 views
The equilibrium constant (Kp) for the interconversion of PCl5 and PCl3 is 0.0121:PCl5 (g) ↔ PCl3 (g) + Cl2 (g) A vessel is
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2. asked by Zack
3. 11,947 views
At 250ºC, the equilibrium constant Kp for the reaction PCl5(g) PCl3(g) + Cl2(g)is 1.80. Sufficient PCl5 is put into a reaction
1. 1 answer
2. asked by viamariam
3. 162 views