A 0.188g sample of unknown

  1. Instead of using ratios for back titrations we can also use molarities if our solutions are standardized. A 0.188g sample of
    1. answers icon 0 answers
    2. Caroline asked by Caroline
    3. views icon 692 views
  2. Instead of using ratios for back titrations we can also use molarities if our solutions are standardized. A 0.188g sample of
    1. answers icon 3 answers
    2. Caroline asked by Caroline
    3. views icon 787 views
  3. A 0.188g sample of unknown metal, X (s), produced 71.4 ml of hydrogen gas when reacted with HCL according to the equation:
    1. answers icon 2 answers
    2. K asked by K
    3. views icon 1,209 views
  4. Need help solving this problem.A 0.188g sample of unknown metal, X (s), produced 71.4ml of hydrogen gas when reacted with HCl
    1. answers icon 2 answers
    2. Louis asked by Louis
    3. views icon 2,839 views
  5. if the ration of water drops to EDTA is 6.7 for the known sample and 10 for the unknown sample what is the concentration of the
    1. answers icon 3 answers
    2. alex asked by alex
    3. views icon 1,183 views
  6. a distribution of scores has 6, but the value of the mean is unknown, a researcher plans to select a sample from the population
    1. answers icon 0 answers
    2. herry asked by herry
    3. views icon 568 views
  7. A 0.642 g sample of an unknown gas was collected over water at 25 C and 1.04 atm. The collection cylinder contained 151.3 mL of
    1. answers icon 2 answers
    2. Anonymous asked by Anonymous
    3. views icon 2,028 views
  8. a 1.32g sample on unknown containing KHP as a component was titrated with 22.48mL of 0.105 M NaOH to a pheolphthalein end point.
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 792 views
  9. A 0.12 g sample of unknown was placed in a flask and dissolved in 125 mL of deionized water. A solution of HCl (0.10 M) was used
    1. answers icon 1 answer
    2. Stephanie asked by Stephanie
    3. views icon 605 views
  10. A 0.18 g sample of unknown was placed in a flask and dissolved in 125 mL of deionized water. A solution of HCl (0.13 M) was used
    1. answers icon 1 answer
    2. Taylor asked by Taylor
    3. views icon 618 views