Asked by Anonymous
a 1.32g sample on unknown containing KHP as a component was titrated with 22.48mL of 0.105 M NaOH to a pheolphthalein end point. what is the weight percent of KHP in the unknown sample?
Answers
Answered by
DrBob222
KHP + NaOH ==> NaKP + H2O
mols NaOH = M x L = ?
mols KHP = mols NaOH since the reaction is 1:1
grams KHP = mols KHP x molar mass KHP.
%KHP = (mass KHP/mass sample)*100 = ?
mols NaOH = M x L = ?
mols KHP = mols NaOH since the reaction is 1:1
grams KHP = mols KHP x molar mass KHP.
%KHP = (mass KHP/mass sample)*100 = ?
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