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A 0.0230 g sample of

  1. What volume of 0.125 M KMnO4 is required to yield 0.180 mol of potassium permanganate, KMnO4?Responses 22. L 22. L 0.0230 L
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  2. @DrBob222I am stuck, x=1.590 g of k2CO3=> x+y=2.118 1.590+y=2.118 => y=0.528 g of KHCO3 then 0.528 g to moles 2x+0.00527
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    2. mike asked by mike
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  3. A 0.0230 g sample of an unknown was dissolved in 2.260 g of benzene. The molality of this solution, determined by freezing point
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    2. Crystal asked by Crystal
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  4. Which of the following statements about the two sample sizes is NOT true? Assume thepopulation standard deviations are equalA.
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    2. arelis asked by arelis
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  5. Calculate the pH at the stoichiometric point of a titration of 25.0 mL of 0.120 M benzoic acid with 0.0230 M NaOH
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    2. lawerence asked by lawerence
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  6. Which base listed below would be the best to creat a buffer having a pH of 5.0230?hydrazine, Kb = 8.90e-7 methylamine, Kb =
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    2. hershi asked by hershi
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  7. What volume (in milliliters) of 0.180 M NaOH should be added to a 0.135 L solution of 0.0230 M glycine hydrochloride (pKa1 =
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    2. Deena12 asked by Deena12
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  8. Let us assume that Cu(OH)2(s) is completely insoluble, which signifies that the precipitation reaction with NaOH(aq) (presented
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    2. Anonymous asked by Anonymous
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  9. What volume (in milliliters) of 0.180 M NaOH should be added to a 0.135 L solution of 0.0230 M glycine hydrochloride (pKa1 =
    1. answers icon 1 answer
    2. Deena12 asked by Deena12
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  10. Sodium sulfate is slowly added to a solution containing 0.0500 M Ca2 (aq) and 0.0230 M Ag (aq). What will be the concentration
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    2. john asked by john
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