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9.8g of iron(II)salt FeSO4.(NH4)2.6H2O was

4.0 gram of ferrous ammonium sulphate, FeSO4*(NH4)2SO4 * 6H2O, is used. Since the oxalate is in excess , Calculate the
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2. asked by Kesha
3. 1,821 views
4.0 gram of ferrous ammonium sulphate, FeSO4*(NH4)2SO4 * 6H2O, is used. Since the oxalate is in excess , Calculate the
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2. asked by Pat
3. 1,052 views
9.8g of iron(II)salt FeSO4.(NH4)2.6H2O was dissolved in dilute sulphuric(VI)acid.Distilled water was added to it and made up to
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9.8g of iron(II)salt FeSO4.(NH4)2SO4.6H2O was dissolved in dissolved in dilute sulphuric(VI)acid.Distilled water was added to it
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Consider the salt FeSO4.7H20.What quantity in grams of salt could be produced from 1g of iron, assuming the overall reaction
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2. asked by Matt
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Charges on the metalMgSO4 = +2 NiSO4*6H2O = +2 CoCl2*6H2O = +2 KCr(SO4)2*12H2O = +3 CuSO4*5H2O = +2 (NH4)2Cr2O7 = +2 FeSO4*7H2O
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2. asked by ...
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Pls how can I carry out qualitative analysis on iron 11 ammonium sulphate hexahydrate (NH4)2SO4.FeSO4.6H2O in a secondary school
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2. asked by jibaorex
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If it is known that the iron(ii) salt is FeSO4.7H20 calculate the %Fe from the formula
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2. asked by Revash Singh
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4.0 g of ferrous ammmonium sulphate, FeSO4(NH4)2SO4 6H2O, is used. Since the oxalate is in excess, calculate the theoretical
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2. asked by Serena
3. 1,083 views
4.0 gram of ferrous ammonium sulphate, FeSO4*(NH4)2SO4 * 6H2O, is used. Since the oxalate is in excess , Calculate the
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2. asked by Anonymous
3. 923 views