2SO2(g) + O2(g) ---> 2SO3

  1. If sulfur dioxide and oxygen can be made into sulfur troxide, what is the reverse reaction?2SO3-->2SO2+O2*** SO3+O2-->SO5
    1. answers icon 0 answers
    2. Jordan asked by Jordan
    3. views icon 786 views
  2. At a certain temperature , 0.960 mol of SO3 is placed in a 3.50 L container.2SO3 ----> 2SO2 + O2 At equilibrium , 0.190 mol of
    1. answers icon 2 answers
    2. Alexis Moran asked by Alexis Moran
    3. views icon 2,957 views
  3. 17. You have the following equations:2S (s) + 3O2 (g) 2SO3 (g), H = 792 kJ 2S (s) + 2O2 (g) 2SO2 (g), H = ? 2SO2 (g) + O2 (g)
    1. answers icon 1 answer
    2. JoJo asked by JoJo
    3. views icon 3,047 views
  4. 2 SO2(g) + O2(g) <==> 2SO3(g)Initially, 1.6mol SO3 is placed in a 3.0L container. At equilibrium, [O2] = 0.15M. What is the
    1. answers icon 4 answers
    2. Jessica asked by Jessica
    3. views icon 1,377 views
  5. S(s) + O2(g) → SO2(g) =x2SO3(g) →2SO2(g) + O2(g)=y Based on the information in the table above, which of the following
    1. answers icon 1 answer
    2. - asked by -
    3. views icon 133 views
  6. according to the balanced chemical equation 2SO2<--- 2 is a subscript...so anyway it's 2SO2+ O2 ----> 2SO3How many liters of
    1. answers icon 2 answers
    2. lanony(please help) asked by lanony(please help)
    3. views icon 630 views
  7. Calculate the enthalpy change for the reaction:2S(s) + 3O2(g) --> 2SO3(g) Use the following thermochemical equations: Reaction
    1. answers icon 2 answers
    2. Jordin asked by Jordin
    3. views icon 7,353 views
  8. Sulfur burns in oxygen in two steps:i.S(s) + O2(g) ->SO2(g) change of Heat=-297kJ ii. 2SO2(g) + O2(g)->2SO3(g) change of
    1. answers icon 1 answer
    2. Erika asked by Erika
    3. views icon 866 views
  9. Would you balance this oneSO2 + O2. SO3 Like 2SO2 + O2. 2SO3
    1. answers icon 1 answer
    2. Carol asked by Carol
    3. views icon 415 views
  10. At a certain temperature, 0.660 mol of SO3 is placed in a 3.00 L container.2SO3=>2SO2+O2 Kc=
    1. answers icon 0 answers
    2. Josh asked by Josh
    3. views icon 599 views