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A 0.2528 g sample of a mixture containing sodium carbonate and sand requires 12.32 mL of 0.2409 M HCl(aq). Assuming that the sand does not react with the HCl(aq), what percentage of the mixture is sodium carbonate? Balanced equation: Na2CO3(s) + 2 HCl(aq)...

When 25.0 g of ethanol vapor condenses, 23.6 kJ of heat is released. How much heat is required in kJ to vaporize 254 g of ethanol?

A 2.25 g sample of hydrazine, N2H4, is burned in a bomb calorimeter that contains 6,402.45 g of H2O, and the temperature increases from 25.00° C to 26.17° C. The heat capacity of the calorimeter is 3.64 kJ/° C. Calculate Delta E for the combustion of N2H4...

The unbalanced equation for the combustion of ethanol is as follows: C2H5OH(l) + O2(g) ¨ CO2(g) + H2O(g) How much heat, in kJ, is liberated when 4.84 kg of C2H5OH(l) is burned? Species Delta H‹f (kJ/mol) H2O(g) -241.8 CO2(g) -393.5 C2H5OH(l) -277.7 Expr...

Copper metal can be obtained by heating copper oxide in the presence of carbon monoxide, CO, according to the reaction: CuO(s) + CO(g) --> Cu(s) + CO2(g) Calculate Delta H° in kJ using the following thermochemical equations. Reactions 2CO(g) + O2(g) --> 2...

Calculate the enthalpy change for the reaction: 2S(s) + 3O2(g) --> 2SO3(g) Use the following thermochemical equations: Reaction S(s) + O2(g) --> SO2(g) Delta H(in kJ) -296.8 2SO2(g) + O2(g) --> 2SO3(g) Delta H(in kJ) -197.0

What led to the end of Egypt's power in the Nile River valley

Crude oil is a mixture of many different components. The extraction of crude oil from the Earth is important, but its refinement into different substances is a key piece to obtaining as many uses as possible from the crude oil. Using the diagram, justify...

Thank you! So, is this correct? moles HCl = M x L = .2409 X .01232 = .00297 moles Na2CO3 = 1/2 moles HCl (from the equation). = .00297 / 2 = .00148 g Na2CO3 = moles x molar mass .00148 X 106 = .157 %Na2CO3 = (mass Na2CO3/mass sample)*100 = ?? .157 / .2528...

Oh ok, I see what I did now. Thank you for the help! : )

ya Mum.

the answer is C.

2.4 meters