2ClO2 + 2OH- --> ClO2-

i need help with this pre lab question:|plse help me! teh following data were obained for the reaction 2ClO2(aq)+ 2OH^-(aq) ->
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2ClO2 + 2OH- --> ClO2- + H2OExperiment 1, M of [ClO2] = .060 M of [OH-] = .030 Rate of disappearance of ClO2 (M/s) = .0248
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i need help with a rate law question:The reaction is 2ClO2(aq) + 2OH -(aq)---> ClO3-(aq)+ ClO2-(aq) + H2O(l) Experiment 1:
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The reaction 2ClO2(aq)+2OH−(aq)→ClO3−(aq)+ClO2−(aq)+H2O(l)
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Redox reaction of cl2 --> cl ion and clo2-I split it up into two half reactions cl2-->2cl- and cl2-->2clo2-
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If HClO2 is a stronger acid than HF, which is stronger than HOCl, thenthe order of strengths of the conjugate bases of these
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Chlorine dioxide reacts in basic water to form chlorite and chlorate according to the following chemical equation:2ClO2(aq) +
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pre-lab questin..part a was to determine the rate law from the given table... finally i was able to calculate ..rate law which
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ClO2 is sometimes used as a chlorinating agent for water treatment.Cl2 + 4 NaClO -> 4 NaCl + 2 ClO2 In an experiment, 1L Cl2
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An electrochemical cell is based on these two half-reactions:Ox: Sn(s) → Sn2+(aq, 1.74 M) + 2 e- Red: ClO2(g, 0.120 atm) + e-
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