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2C8H18(g)+25O2(g)+16CO2(g)+18H2O(g) 0.290mol of octane is allowed to react with 0.600mol
2C8H18(g)+25O2(g)+16CO2(g)+18H2O(g)
0.290mol of octane is allowed to react with 0.600mol of oxygen.The limiting reactant is
1 answer
asked by
Rose
1,273 views
2C8H18(g)+25O2(g)-->16CO2(g)+18H2O(g)
0.290mol of octane is allowed to react with 0.600mol of oxygen.The limiting reactant is
2 answers
asked by
Rose
3,129 views
This balance equation shows the burning of octane in air. 2C8H18 + 25O2 ----> 16CO2 + 18H2O. How many grams of carbondioxide
1 answer
asked by
Shane
848 views
My balanced equation is:
a) 2C8H18(g) + 25O2(g) -> 16CO2(g) + 18H2O(g) b) 0.290 mol of octane is allowed to react with 0.670mol
4 answers
asked by
K
8,108 views
0. A common gasoline additive is octane, C8H18. When octane is burned it produces heat
according to the following equation.
1 answer
263 views
Calculate the standard enthalpy change for the reaction:
2C8H18(l) + 17O2(g) --> 16CO(g) + 18H2O(l) Given: 2C8H18(l) + 25O2(g)
1 answer
asked by
Anon
2,125 views
HOW MANY GRAMS OF OCTANE WOULD BE NEEDED TO RELEASE 3,500 kJ OF HEAT?
2C8H18 + 25O2-----> 16CO2 + 18H2O DeltaH= -5,530 kJ/mole of
1 answer
asked by
Matthew
728 views
What mass of oxygen gas, O2, from the air is consumed in the combustion of 702 g of octane, C8H18, one of the principal
1 answer
asked by
Jeremiah latkuoth
41 views
Calculate the standard enthalpy change for the reaction 2C8H18(l)+17O2(g)> 16CO(g) + 18H2O(l)
Given
2 answers
asked by
Nicole
4,218 views
During the combustion of 5.00 g of octane, C8H18, 239.5 kcal (1002 kJ) is released.
Balanced equation: 2C8H18+25O2→16CO2+18H2O
1 answer
asked by
Timbs
1,550 views