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1.5 mole of PCl5 are

PCl5 dissociates according to the reaction: PCl5(g) ↔ PCl3(g) + Cl2(g). One mole of PCl5 was placed in one liter of solution.
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2. asked by Sam
3. 3,441 views
1.5 mole of PCl5 are heated at constant temperature in a closed vessel of 4 litres capacity.At the equilibrium,PCl5 is 35percent
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2. asked by Chador
3. 4,605 views
PCL5=PCl3+Cl2a. Initially 0.72 mole PCl5 are placed in 1.50 L flask. At equilibrium, there is 0.16 mole PCl3 in the flask. What
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2. asked by chemdummy79
3. 1,563 views
For the following reaction at 600. K, the equilibrium constant, Kp, is 11.5.PCl5(g) = PCl3(g) + Cl2(g) Suppose that 2.510 g of
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2. asked by Writeacher
3. 3,035 views
At a certain temperature, .5 mol of PCl5 was placed in a .25 L vessel and permitted to react as shownPCl5 (g) --> PCl3 (g)+ Cl2
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2. asked by Alex
3. 658 views
For the following reaction at 600. K, the equilibrium constant, Kp is 11.5.PCl5(g) PCl3(g) + Cl2(g) Suppose that 3.314 g of PCl5
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2. asked by Anonymous
3. 1,211 views
At a certain temperature, 2.00 moles of phosphorus(V) chloride, PCl5, was placed in a 1.0 L vessel and permitted to react as
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2. asked by chem
3. 614 views
for each mole of PCL5 which dissociates, how many moles of CL2 are produced
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2. asked by bec
3. 620 views
a sample of pcl5 weighing 2.69 placed in 1.0 l flask and completely vaporized at a tem of 250 c the pressur at this tempreture
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2. asked by biran
3. 1,117 views
a sample of pcl5 weighing 2.69 placed in 1.0 l flask and completely vaporized at a tem of 250 c the pressur at this tempreture
1. 1 answer
2. asked by biran
3. 507 views