Zinc reacts with hydrochloric acid according to the reaction equation:

Zn(s)+2HCl(aq)->ZnCl2(aq)+H2(g)

How many milliliters of 4.50M HCl1(aq) are required to react with 8.25g of an ore containing 30.0% Zn(s) by mass?

2 answers

convert .30*8.25g to moles Zn

You need twice that number of moles of HCL

molesneeded=litersacid*4.5
conver that to ml.
5849