Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCL(aq)=>ZnCl2(aq)+H2(g). How many mm of 1.50M HCL(aq) are required to react with 9.05 g of ZN?

Answer 1

Zn + 2HCl ==> ZnCl2 + H2

mols Zn = grams/atomic mass Zn
Convert mols Zn to mols HCl using the coefficients in the balanced equation.
Then convert mols HCl to volume using M = mols/L. You know mols and M, solv for L and convert to mL.
By the way, that is mL and not mm.

Answer 2

92.28