To solve the system from part (a), we need to set up two equations based on the given information.
Let's assume each solo act lasts x minutes and each ensemble act lasts y minutes.
From the given information, we know that there will be 16 solo acts and 3 ensemble acts in the first show. Since the show lasts 129 minutes, we can set up the equation:
16x + 3y = 129
From the given information, we also know that in the second show, there will be 8 solo acts and 3 ensemble acts. Since the show lasts 81 minutes, we can set up the equation:
8x + 3y = 81
Now, we can solve this system of equations using any method. Let's use substitution.
From the second equation, we can rearrange it to solve for y:
3y = 81 - 8x
y = (81 - 8x) / 3
Substitute this expression for y into the first equation:
16x + 3((81 - 8x) / 3) = 129
Multiply through by 3 to get rid of the fraction:
16x + 81 - 8x = 387
Combine like terms:
8x + 81 = 387
Subtract 81 from both sides:
8x = 306
Divide both sides by 8:
x = 38.25
Now substitute this value of x into the second equation to find y:
8(38.25) + 3y = 81
306 + 3y = 81
3y = -225
y = -75
Therefore, the solution to the system is (x, y) = (38.25, -75).
Your school's talent show will feature 16 solo acts and 3 ensemble acts. The show will last 129 minutes. The 8 solo performers judged best will give a repeat performance at a second 81 minute show, which will also feature the 3 ensemble acts. Each solo act lasts x minutes, and each ensemble act lasts y minutes. Use this information to answer parts (a) and (b)
b) Solve the system from part (a)
[ ] (Type an ordered pair.)
3 answers
Part C) How long is each solo act?
From the solution to the system of equations in part (b), we found that x = 38.25.
Therefore, each solo act lasts 38.25 minutes.
Therefore, each solo act lasts 38.25 minutes.