Part A:
Let's assume that each solo act lasts x minutes and each ensemble act lasts y minutes.
Since there will be 12 solo acts and 2 ensemble acts in the first show, the total number of acts in the first show is 12 + 2 = 14.
The total time for the first show is given as 90 minutes.
So, the first equation based on the total time of the first show is:
12x + 2y = 90
In the second show, only the 6 best solo acts are repeated. So, the total number of acts in the second show is 6 + 2 = 8.
The total time for the second show is given as 60 minutes.
So, the second equation based on the total time of the second show is:
6x + 2y = 60
Part B:
To solve this system of equations using the elimination method, we can multiply the first equation by 3 and the second equation by 5 to eliminate the y term:
First equation: 3(12x + 2y) = 3(90)
36x + 6y = 270
Second equation: 5(6x + 2y) = 5(60)
30x + 10y = 300
Now, subtract the second equation from the first equation:
(36x + 6y) - (30x + 10y) = 270 - 300
6x - 4y = -30
Since the coefficients of the y term are the same, subtracting the two equations eliminated the y term, leaving us with a single equation in terms of x.
To solve for x, divide both sides of the equation by 6:
(6x - 4y)/6 = -30/6
x - (2/3)y = -5
So, the equation in terms of x is x - (2/3)y = -5.
Since we're asked to find the length of each solo act, we're looking for the value of x. However, the equation in terms of x and y doesn't provide enough information to determine the exact value of x. To find the length of each solo act, we would need additional information or equations.
Your school's talent show will feature 12 solo acts and 2 ensemble acts. The show will last 90 minutes. The 6 solo performers judged best will give a repeat performance at a second 60-minute show, which will also feature the 2 ensemble acts. Each solo act lasts x minutes, and each ensemble act lasts y minutes.
Part A
Write a system of equations to model the situation.
Part B
How long is each solo act?
work using the elimination method.
1 answer