Asked by Nahla
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If the ball is either blue or white, what is the probability that it was drawn from urn Y?
Assume that you randomly pick one of the urns: X, Y, or Z. You then randomly draw one ball out of the selected urn and note its color. The urns contain the following colored balls:
Urn X: 2 red, 1 white, and 2 blue.
Urn Y: 1 red, 2 white, and 3 blue.
Urn Z: 1 red, 2 white, and 1 blue.
If the ball is either blue or white, what is the probability that it was drawn from urn Y?
For this problem I did this and I can't figure out why it is wrong:
Pr(drawn from Y urn/is blue) + Pr(drawn from Y urn/ is
white)
(10/23)+(10/31)=540/713
If the ball is either blue or white, what is the probability that it was drawn from urn Y?
Assume that you randomly pick one of the urns: X, Y, or Z. You then randomly draw one ball out of the selected urn and note its color. The urns contain the following colored balls:
Urn X: 2 red, 1 white, and 2 blue.
Urn Y: 1 red, 2 white, and 3 blue.
Urn Z: 1 red, 2 white, and 1 blue.
If the ball is either blue or white, what is the probability that it was drawn from urn Y?
For this problem I did this and I can't figure out why it is wrong:
Pr(drawn from Y urn/is blue) + Pr(drawn from Y urn/ is
white)
(10/23)+(10/31)=540/713
Answers
Answered by
gabby
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