Mint (aa) would be represented by q^2, where q is the frequency of the recessive allele in the population. Since p+q=1, we can solve for q.
Given that 80% of the prey population is chocolate (AA), p=0.8 and q=0.2.
Therefore, the frequency of mint (aa) in the remaining prey population would be q^2 = 0.2^2 = 0.04 or 4%.
So, 4% of the remaining prey population would be mint (aa).
Option a: 1%
Your class is participating in a population genetic simulation. You and your classmates are the predators and your prey is candy in a jar: chocolate (AA), chocolate and mint (Aa), and mint (aa). Each time you and your classmates eat one candy, your prey reproduces (more candy is added to the jar). After several generations you observe 80% of the prey remaining in the jar is chocolate (AA). What percent of your remaining prey is mint (aa) assuming that Hardy-Weinberg equilibrium is being followed?
AA=P^2=80%=0.8
a
1%
b
10%
c
80%
d
89%
1 answer