Your body deals with excess nitrogen by excreting it in the form of urea, NH2CONH2. The reaction producing it is the combination of arginine (C6H14N4O2) with water to give urea and ornithine (C5H12N2O2).

Question

Your body deals with excess nitrogen by excreting it in the form of urea, NH2CONH2.  The reaction producing it is the combination of arginine (C6H14N4O2) with water to give urea and ornithine (C5H12N2O2).
C6H14N4O2  +  H2O    NH2CONH2  +  C5H12N2O2
		[Molar masses:              174.2           18.02           60.06                132.2]
	If you excrete 95 mg of urea, what quantity of arginine must have been used?  What quantity of ornithine must have been produced?

Anonymous · Accepted Answer

i got .276g of arginine and .209g of ornithine

DrBob222 · Answer

You can use this simple stoichiometry example I've posted. Just follow the steps. http://www.jiskha.com/science/chemistry/stoichiometry.html

Joey · Answer

O OK

Anonymous · Answer

.0276