You toss a tennis ball straight upward. At the moment it leaves your hand it is at a height of 1.3 m above the ground, and it is moving at a speed of 7.4 m/s.

(a) How much time does it take for the tennis ball to reach its maximum height?

(b) What is the maximum height above the ground that the tennis ball reaches?

(c) When the tennis ball is at a height of 2.6 m above the ground, what is its speed?

1 answer

total energy at launch=total energy at top

1/2 m v^2+ mghi=mgIhmax)
1/2 (7.4^2)+9.8(1.3)=9.8(hmax)
solve for hmax

time?
hmax=hi+vi*time-1/2 g t^2
solve for time t.