a. mass*g*height
b. KE at bottom= mgh+1/2 m vi^2
= m(25*9.8)+m (1/2*16)
but KE at bottom=1/2 m vf^2
so vf=sqrt (2*25*9.8 +16)
You throw a 5.5 g coin straight down at 4.0 m/s from a 25-m-high bridge.
A) How much work does gravity do as the coin falls to the water below?
B)What is the speed of the coin just as it hits the water?
6 answers
A:(5.5g)(9.81m/s^2)(50m)+ 2698g*m^2/s^2
B:32m/s
B:32m/s
A:(5.5g)(9.81m/s^2)(50)=2698g*m^2/s^2
30m/s
A) Mass X g X height
Change the mass into kg
(.0055) X 9.8 X 25
Change the mass into kg
(.0055) X 9.8 X 25
Do not forget to convert the grams to kg to get the right answer.
1 answer