standing on the ground, you throw a 0.55 kg lunch bag at a friend, you manage to throw the bag straight up (vertically) using 50 J of energy to throw it there is also a crosswind of 0.5 m/s. How high will the bag travel before all of its kinetic energy is converted into gravitational potential energy?

1 answer

KE=PE
KE=mgh

h=KE/mg =50/0.55•9.8 =9.28 m