You randomly draw marbles from a bag containing both blue and green marbles, without replacing the marbles between draws. If B=drawing a blue marble and G=drawing a green marble, which represents the probability of drawing a blue marble first and a green marble second?

Question

You randomly draw marbles from a bag containing both blue and green marbles, without replacing the marbles between draws. If B=drawing a blue marble and G=drawing a green marble, which represents the probability of drawing a blue marble first and a green marble second?
  A. P(B)⋅P(G)
  B. P(B and G)
  C. P(G after B)
  D. P(B, then G)

Anonymous · Accepted Answer

Suppose a bag contains 3 blue and 2 green marbles. You randomly draw 2 marbles without replacement. If B=drawing a blue marble and G=drawing a green marble, which event does NOT have the same probability as the others?
Bag
A. GG
B. BB
C. GB
D. BG

Damon · Answer

You are not replacing, so A is hopelessly out

The probability of drawing a green CHANGES after your first draw if you do not replace.
Only one choice is specific about drawing blue first and green second.

nhbvdfxd · Answer

yhngrbfeds