Asked by Anie
Two marbles are drawn randomly (without replacement) from a bag containing two green, three yellow, and four red marbles. Find the probability of the event.
Drawing two red marble
step 1 - found it!
STEP 2: Find the number of ways of choosing two marbles.
ways
STEP 3: Find the number of ways of choosing two red marbles.
STEP 4: Find the probability of choosing two red marbles.
Drawing two red marble
step 1 - found it!
STEP 2: Find the number of ways of choosing two marbles.
ways
STEP 3: Find the number of ways of choosing two red marbles.
STEP 4: Find the probability of choosing two red marbles.
Answers
Answered by
Reiny
following your "steps"
prob(both red) = C(4,2)/C(9,2)
= 6/36
= 1/6
or , straightforward way ....
prob = (4/9)(3/8) = 1/6
prob(both red) = C(4,2)/C(9,2)
= 6/36
= 1/6
or , straightforward way ....
prob = (4/9)(3/8) = 1/6
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