normal force on floor = 750 sin 25 + 9.81 m
friction force =.73(750 sin 25 + 9.81 m)
so
750cos25 = .73(750 sin 25 + 9.81 m)
solve for m
You push downward on a box at an angle 25° below the horizontal with a force of 750 N. If the box is on a flat horizontal surface for which the coefficient of static friction with the box is 0.73, what is the mass of the heaviest box you will be able to move?
5 answers
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