how far can you jump with that speed and angle? The range is
R = v^2/g sin2θ
Now that you know the distance, figure your time in the air, with a constant speed of v cosθ.
Now, how far does the board go in that time?
You can't be farther away than the difference in distances.
You push a skateboard so that it rolls down the road at a speed of 0.600 m/s. You run after the skateboard at a speed of 3.50 m/s and while still behind the skateboard you jump off the ground at an angle of 22.0° above the horizontal hoping to land on the skateboard. How much distance do you need between you and the skateboard to jump and land on it?
1 answer
0 answers