Yes.
7.45 = pKa2 + log (b/a)
b/a = ?
You need to use KH2PO4 and K2HPO4 to prepare a buffer with a pH of 7.45. Which of the following ratios of [base]/[acid] is required? For phosphoric acid, (H3PO4), Ka2 = 6.2 × 10–8.
Do I use the Hasselbach equation?
1 answer