To prepare a 3M solution of hydrochloric acid from the stock solution of 98%, we need to dilute the stock solution appropriately. Let's assume we need a final volume of 200 ml of the 3M solution.
We can use the following formula to calculate the volume of stock solution we need to take and the volume of water we need to add:
C1V1 = C2V2
where C1 is the concentration of the stock solution (98%), V1 is the volume of stock solution we need to take, C2 is the desired concentration (3M), and V2 is the final volume of the solution (200 ml).
Rearranging the formula, we get:
V1 = (C2V2)/C1
Substituting the values, we get:
V1 = (3 x 200)/0.98
V1 = 612.24 ml
This means we need to take 612.24 ml of the stock solution and add water to make a final volume of 200 ml. We can calculate the volume of water needed as:
Volume of water = V2 - V1
= 200 - 612.24
= -412.24 ml
This negative value means we need to subtract 412.24 ml of the stock solution from 200 ml of water to get the final volume of 200 ml.
Therefore, to prepare a 3M solution of hydrochloric acid from the stock solution of 98%, we need to mix 612.24 ml of the stock solution with 412.24 ml of water to get a final volume of 200 ml.
This solution can be used to neutralize the alkaline toxic produced by the wasp sting.
You have received a patient who has stung by waps which produce an alkaline toxic whose concentration is estimated at 3M(mole per cubic decimeter ).unfortunately there is no acid substance in the pharmacy with the same concetration as the toxic produced by wasps that can be given to the patient in order to directly neutralize the base .However the lab has a bottle of aqueous hydrochloric acid whose concentration is 98% .Describe with appropriate calculation how you could prepare a 3M(3mole per cubic decimeter) solution with a volume of 200ml from stock solution (3MHC),so that you use on a patient to neutralize the alkaline toxic?
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