First, we need to calculate the number of moles of sodium hydroxide present in the solution:
moles of NaOH = mass of NaOH / molar mass of NaOH
moles of NaOH = 428g / 40.00g/mol (molar mass of NaOH)
moles of NaOH = 10.70 mol
Next, we need to calculate the molarity:
molarity = moles of solute / volume of solution
molarity = 10.70 mol / 6.4 L
molarity = 1.67 M
Therefore, the molarity of the sodium hydroxide solution is 1.67 M.
You have a sample which consists of 428g sodium hydroxide (NaOH)
dissolved in enough water to make a final solution of 6.4l. What is the
molarity?
1 answer
1 answer