You have a sample which consists of 428g sodium hydroxide (NaOH)

dissolved in enough water to make a final solution of 6.4l. What is the
molarity?

1 answer

First, we need to calculate the number of moles of sodium hydroxide present in the solution:

moles of NaOH = mass of NaOH / molar mass of NaOH
moles of NaOH = 428g / 40.00g/mol (molar mass of NaOH)
moles of NaOH = 10.70 mol

Next, we need to calculate the molarity:

molarity = moles of solute / volume of solution
molarity = 10.70 mol / 6.4 L
molarity = 1.67 M

Therefore, the molarity of the sodium hydroxide solution is 1.67 M.