The Ag^+ and the CrO4^2- react to form Ag2CrO4 but the NO3^- is not involved in the reaction (it is a spectator ion); therefore, it's concentration is not affected. It will be diluted, of course, due to the added volume from the Na2CrO4.
2.15 M x [(125/(125+75)] = ? M.
You have 75.0 mL of a 2.50 M solution of Na2CrO4 (aq). You also have 125 mL of a 2.15 M solution of AgNO3 (aq). Calculate the concentration of NO3 when the two solutions are added together.
1 answer
3 answers