mL1 x M1 = mL2 x M2
67.0 x 0.4M = mL2 x 0.1M
Solve for mL2 which will be the TOTAL volume. Since you had 67.0 mL initially, subtract from the total to find how much must be added.
You have 67.0 mL of a 0.400 M stock solution that must be diluted to 0.100 M. Assuming the volumes are additive, how much water should you add?
2 answers
26.7
1 answer