each revolution travels 2πr = 68π cm. So,
3900cm/s * 1rev/68πcm = 3900/68π rev/s
That gives you frequency. Flip it upside down to get the period.
the angular speed is the linear speed divided by 2π.
You drive down the road at 39 m/s (88 mi/h) in a car whose tires have a radius of 34 cm.
What is the period of rotation of the tires?2sf value/units
Through what angle does a tire rotate in one second?2sf value/ units
4 answers
period? Time=distance/2PIr=39m/s /.34*PI=
2PIr/39m/s= .0548sec
each rotation of 2PI occurs in that time, so in one second it
angle= 2PI*1/.0548 radians
2PIr/39m/s= .0548sec
each rotation of 2PI occurs in that time, so in one second it
angle= 2PI*1/.0548 radians
dang - I meant the angular speed is the rotational speed (rev/s) times 2π.
i couldn't find the answer for part one still is wrong pls help
You drive down the road at 39 m/s (88 mi/h) in a car whose tires have a radius of 34 cm.
What is the period of rotation of the tires?2sf value/units
Through what angle does a tire rotate in one second?2sf value/ units
physics help - Steve, Saturday, April 29, 2017 at 4:46pm
each revolution travels 2πr = 68π cm. So,
3900cm/s * 1rev/68πcm = 3900/68π rev/s
That gives you frequency. Flip it upside down to get the period.
the angular speed is the linear speed divided by 2π.
physics help - bobpursley, Saturday, April 29, 2017 at 4:46pm
period? Time=distance/2PIr=39m/s /.34*PI=
2PIr/39m/s= .0548sec
each rotation of 2PI occurs in that time, so in one second it
angle= 2PI*1/.0548 radians
@bobpursley gets it right - Steve, Saturday, April 29, 2017 at 6:00pm
dang - I meant the angular speed is the rotational speed (rev/s) times 2π.
You drive down the road at 39 m/s (88 mi/h) in a car whose tires have a radius of 34 cm.
What is the period of rotation of the tires?2sf value/units
Through what angle does a tire rotate in one second?2sf value/ units
physics help - Steve, Saturday, April 29, 2017 at 4:46pm
each revolution travels 2πr = 68π cm. So,
3900cm/s * 1rev/68πcm = 3900/68π rev/s
That gives you frequency. Flip it upside down to get the period.
the angular speed is the linear speed divided by 2π.
physics help - bobpursley, Saturday, April 29, 2017 at 4:46pm
period? Time=distance/2PIr=39m/s /.34*PI=
2PIr/39m/s= .0548sec
each rotation of 2PI occurs in that time, so in one second it
angle= 2PI*1/.0548 radians
@bobpursley gets it right - Steve, Saturday, April 29, 2017 at 6:00pm
dang - I meant the angular speed is the rotational speed (rev/s) times 2π.