To find the coordinates of point D, we need to use the fact that a rectangle has parallel sides, so the vector from B to C is perpendicular to the vector from C to D. We can use this idea to find the coordinates of D as follows:
1. Find the vector from B to C:
BC = (−3,7.5) − (−3,2.5) = (0,5)
2. Find a vector perpendicular to BC:
One way to do this is to swap the components of BC and negate one of them, like so:
BC' = (5,0) or (−5,0)
Either of these vectors is perpendicular to BC.
3. Add the vector BC' to point A to get point D:
AD = BC'
D = A + AD = (−7,−7.5) + (−5,0) = (−12,−7.5)
Therefore, the coordinates of point D are (−12,−7.5).
You are graphing rectangle ABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the rectangle:
A =(−7,−7.5), B = (−3,7.5), C = (−3,2.5)
What are the coordinates of point D?
8 answers
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ABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle:
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A(2,0)A, left parenthesis, 2, comma, 0, right parenthesis,
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B(6,0)B, left parenthesis, 6, comma, 0, right parenthesis,
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C(6,7)C, left parenthesis, 6, comma, 7, right parenthesis, and
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D(2,7)D, left parenthesis, 2, comma, 7, right parenthesis.
What is the area of rectangle
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ABCDA, B, C, D?
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ABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle:
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A(2,0)A, left parenthesis, 2, comma, 0, right parenthesis,
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B(6,0)B, left parenthesis, 6, comma, 0, right parenthesis,
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C(6,7)C, left parenthesis, 6, comma, 7, right parenthesis, and
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D(2,7)D, left parenthesis, 2, comma, 7, right parenthesis.
What is the area of rectangle
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ABCDA, B, C, D?
To find the area of rectangle ABCDA, we first need to find the length and width of the rectangle. We know that side AB has length 6 - 2 = 4, and side AD has length 7 - 0 = 7. Therefore, the length and width of the rectangle are 7 and 4, respectively.
The area of a rectangle is calculated by multiplying the length by the width, so we have:
Area = Length × Width = 7 × 4 = 28
Therefore, the area of rectangle ABCDA is 28 square units.
The area of a rectangle is calculated by multiplying the length by the width, so we have:
Area = Length × Width = 7 × 4 = 28
Therefore, the area of rectangle ABCDA is 28 square units.
Rectangle
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ABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle:
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A(−7,−5),B(−7,6),A, left parenthesis, minus, 7, comma, minus, 5, right parenthesis, comma, B, left parenthesis, minus, 7, comma, 6, right parenthesis, comma
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C(−4,6)C, left parenthesis, minus, 4, comma, 6, right parenthesis, and
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D(−4,−5)D, left parenthesis, minus, 4, comma, minus, 5, right parenthesis.
Given these coordinates, what is the length of side
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CDC, D of this rectangle?
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ABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle:
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A(−7,−5),B(−7,6),A, left parenthesis, minus, 7, comma, minus, 5, right parenthesis, comma, B, left parenthesis, minus, 7, comma, 6, right parenthesis, comma
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C(−4,6)C, left parenthesis, minus, 4, comma, 6, right parenthesis, and
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D(−4,−5)D, left parenthesis, minus, 4, comma, minus, 5, right parenthesis.
Given these coordinates, what is the length of side
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CDC, D of this rectangle?
To find the length of side CD, we first need to find the coordinates of points C and D. We can see that the y-coordinates of both C and D are 6 and -5, respectively, so we just need to focus on the x-coordinates. We have:
Point C: x = -4
Point D: x = -7
Therefore, the length of side CD is the difference between these x-coordinates:
CD = (-4) - (-7) = 3
So the length of side CD is 3 units.
Point C: x = -4
Point D: x = -7
Therefore, the length of side CD is the difference between these x-coordinates:
CD = (-4) - (-7) = 3
So the length of side CD is 3 units.
You are graphing rectangle ABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the rectangle:
A = (3,5), B = (3,−4),, C = (−2,−4)C,
What are the coordinates of point D?
A = (3,5), B = (3,−4),, C = (−2,−4)C,
What are the coordinates of point D?
1 answer