Asked by Sam
Given: ABCD is a rectangle, diagnoals AC and BD intersect at E
Prove: Triangle AEB is isosceles
Prove: Triangle AEB is isosceles
Answers
Answered by
Reiny
In a previous question you probably proved that in a rectangle the two diagonals are equal and bisect each other, making all 4 smaller segments equal to each other.
Now prove triangles AED and CEB congruent and each is isosceles, and from that angle DAE = angle CBE
therefore their complements are equal.
therefore the base angles of triangle ABE are equal making it isosceles.
Write it up using the method and procedure that your teacher or the course requires.
Now prove triangles AED and CEB congruent and each is isosceles, and from that angle DAE = angle CBE
therefore their complements are equal.
therefore the base angles of triangle ABE are equal making it isosceles.
Write it up using the method and procedure that your teacher or the course requires.
Answered by
maria
find the measure of <2
Answered by
maria
find the measure of <4 and round your answer to the nearest tenth
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