You are bending a wire to make a coat hanger. The length of the wire is 88 centimeters, and 20 centimeters are needed to make a hook hanger. The triangular portion of the hanger is an isosceles triangle. The length of one leg of this triangle is 3/5 the length of the base. Sketch the hanger. Give the dimensions of the triangular portion.

Answer 1

The triangle has a base of length b, and two legs of 0.6b each.

b + 2*.6b + 20 = 88
2.2b = 68
b = 30.9 cm
3/5 b = 18.55 cm

30.9 + 2*18.55 + 20 = 88.0