I would use the NH3 since it would be so easy to overshoot with HCl.
How much NH3? Two approaches, both the same but a different look.
NH3 + HOH ==> NH4^+ + OH^-
Then Kb = (NH4^+)(OH^-)/(NH3)
You know Kb, NH4^+, and OH^- so you can calculate molarity of NH3. From there you go to moles NH3 and from there to drops of the 10.0 M solution to add.
The other approach, I think, is more complicated, but you can use the Henderson-Hasselbalch equation to calculate the base needed; the remainder of the problem is the same as the first one.
You are asked to bring the pH of 0.500L of 0.450M NH4Cl to 7.00.
a) Which of the following solutions would you use: 10.0M HCl or 10.0M NH3?
I figured that one would use the 10.0M NH3
b)How many drops (1 drop 0.05mL) of this solution would you use?
3 answers
can you show calculation plz
how many grams does 90 degree to the third power of aluminum weight if it's density is 2.7cm to the third power is equal V=?
0 answers