For first part i got F= -- kx
x = F/ k
20/150= 0.133m
You apply a force of 20 Nto a compressed spring that has a k= 150m
a) calculate the amount of compression
B) calculate the mass attached to the spring when moving with max speed 6m/s
2 answers
k= 150m
well, units messed up
F = - k x
20 N = -k * x
20 Newtons = -150 Newtons/ meter * x
x = -(20/150) meters
= - 0.133 meters
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one way for part B
max Kinetic energy = max potential energy
(1/2) m v^2 = (1/2) k Xmax^2
m v^2 = 150 * (-0.133)^2 = 2.65
m * 36 = 2.65
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well, units messed up
F = - k x
20 N = -k * x
20 Newtons = -150 Newtons/ meter * x
x = -(20/150) meters
= - 0.133 meters
=======================================
one way for part B
max Kinetic energy = max potential energy
(1/2) m v^2 = (1/2) k Xmax^2
m v^2 = 150 * (-0.133)^2 = 2.65
m * 36 = 2.65
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2 answers