just use the chain rule twice
y = v^2(u(x))
y' = 2v v'(u) u'(x)
y' = -2sin(1/x) cos(1/x) (-1/x^2)
y=-sin^2 (1/x)
find the derivative
1 answer
find the derivative
1 answer
1 answer
1 answer
1 answer
2 answers