If you meant what you wrote, then
a*3b = 3
a*6b = 7
divide and you have 2 = 4
I suspect you meant wither
y = a * x^b
or y = a + x*b
or something else.
y=a⋅xb
whose graph passes through (3, 4) and (6, 7)
2 answers
If your question means:
y = a x - b
then
Equation of a straight line in two point form:
y - y1 = ( y2 - y1 ) ( x - x1 ) / ( x2 - x 1 )
In this case:
x1 = 3 , y1 = 4 , x2 = 6 , y2 = 7
y - 4 = ( 7 - 4 ) ( x - 3 ) / ( 6 - 3 )
y - 4 = 3 ( x - 3 ) / 3
y - 4 = x - 3
Add 4 to both sides
y = x + 1
y = a x - b
then
Equation of a straight line in two point form:
y - y1 = ( y2 - y1 ) ( x - x1 ) / ( x2 - x 1 )
In this case:
x1 = 3 , y1 = 4 , x2 = 6 , y2 = 7
y - 4 = ( 7 - 4 ) ( x - 3 ) / ( 6 - 3 )
y - 4 = 3 ( x - 3 ) / 3
y - 4 = x - 3
Add 4 to both sides
y = x + 1
1 answer