Asked by helpppp
On a day when the sun passes directly overhead at noon, a 1.80-m-tall man casts a shadow of length S(t)=1.8|cot(πt/12)|, where S is the length of shadow in meters and t is the number of hours since 6am, at what time from the following list the length of the shadow would equal to the man’s height?
(A) 3pm (B) 4pm (C) 5pm (D) 6pm (E) never happen
(A) 3pm (B) 4pm (C) 5pm (D) 6pm (E) never happen
Answers
Answered by
oobleck
clearly, when cot(πt/12) = 1
πt/12 = π/4
t = 3
Huh. I get 9am
Note that at noon, t=6, and the shadow has zero length.
πt/12 = π/4
t = 3
Huh. I get 9am
Note that at noon, t=6, and the shadow has zero length.
Answered by
AJ L
For the length of the shadow to be equal to the man's height, then S(t)=1.8, meaning the equation becomes:
1.8=1.8|cot(πt/12)|
1=|cot(πt/12)|
1=1/tan(πt/12)
tan(πt/12)=1
πt/12=π/4
πt=3π
t=3
This means 3 hours after 6am would be 9am, which means none of the times on the list are correct, making option E correct.
1.8=1.8|cot(πt/12)|
1=|cot(πt/12)|
1=1/tan(πt/12)
tan(πt/12)=1
πt/12=π/4
πt=3π
t=3
This means 3 hours after 6am would be 9am, which means none of the times on the list are correct, making option E correct.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.