Asked by Madison
Light with λ = 530 nm passes through a single slit and then illuminates a screen 9.0 m away. If the distance on the screen from the first dark fringe to the center of the interference pattern is 3.20 mm, what is the width of the slit?
Answers
Answered by
Elena
tanα=x/L=3.2•10⁻³/9=3.56•10⁻⁴
tanα≈sinα
bsinα=kλ
b= kλ/sinα=1•530•10⁻⁹/3.56•10⁻⁴=1.5•10⁻³ m
tanα≈sinα
bsinα=kλ
b= kλ/sinα=1•530•10⁻⁹/3.56•10⁻⁴=1.5•10⁻³ m
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