Asked by jessica
Light passes from air into water at an angle of incidence of 40.4°. Determine the angle of refraction in the water.
Answers
Answered by
drwls
I hope you have heard of Snell's law.
N(air)*sin theta(in air)
= N(water)*sin theta (in water)
sin theta (in water) = (1/1.33)sin 40.4 = 0.487
Solve for theta in water
N(air)*sin theta(in air)
= N(water)*sin theta (in water)
sin theta (in water) = (1/1.33)sin 40.4 = 0.487
Solve for theta in water
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.