y=3e^(2x)cos(2x-3) verify that d^2y/dx^2-4dy/dx+8y=0
plz help me i tried all i could but it become too complicated for me
here
set u=3e^(2x) v=cos(2x-3)
du/dx=6e^(2x)
i used chain rule
dv/dx=-2sin(2x-3)
dy/dx=-3e^(2x)sin(2x-3)+cos(2x-3)6e^(2x)
d^2y/dx^2
now i did
lndy/dx=-ln3e^(2x)+lnsin(2x-3)+lncos(2x-3)+ln6e^(2x)
d^2y/dx^2.1/dy/dx=-6e^(2x)/(3e^2(x)+2cos(2x-3)/sin(2x-3)-2sin(2x-3)/cos(2x-3)+12e^(2x)
so whats up any 1 see it too muc
1 answer
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