practising and need help

sir steve plz am a little confuse (x-y)³=A(x+y) prove that (2x+y)dy/dx=x+2y if y is a function of x and x=e^t/(e^t+1) show that dy/dt=x(1-x)dy/dx plz explain to me very well sir damon answered that but i still dont get it If u want me to show my work i wi...

sir steve what about these i just solved it now i didnt get it if x^2+2xy+3y^2=1 prove that (x+3y)^3d^2y/dx^2+2(x^2+2xy+3y^2)=0 i solve with implicit derivative like these 2x+2(xdy/dx+y)+6ydy/dx=0 2x+2xdy/dx+2y+6ydy/dx=0 2xdy/dx+6ydy/dx=-2y-2x (xdy/dx+3yd...

if y=3e^(2x)cos(2x-3) verify that d^2y/dx^2-4dy/dx+8y=0 plz help me i tried all i could but it become too complicated for me here set u=3e^(2x) v=cos(2x-3) du/dx=6e^(2x) i used chain rule dv/dx=-2sin(2x-3) dy/dx=-3e^(2x)sin(2x-3)+cos(2x-3)6e^(2x) d^2y/dx^...

the parametric equation of a curve are x=cos2Øand y=1+sin2Ø find dy/dx and d^2y/dx^2 at Ø=pai/6.find the relationship between x and y sir steve help see my work dx/dØ=-2sin2Ø dy/dØ=2cos2Ø dy/dx=dy/dØ*dØ/dx dy/dx=2cos2Ø*1/-2sin2Ø dy/dx=-cot2Ø d^2y/dx^2=-2c...

k i just practise that now and i got dy/dx=(3(x-y)^2-A)/(A+3(x-y)^2) how did u get dy/dx=-1 plz explain

and also what happen to the orther e^t+1 becus u have x/e^t+1 and in conclusion u said x(1-x)

okay i think i understand now thanks you are good

bart=2p+k=16 lisa=p+2k=11 maggie=p+k solve those 2 up there and that will tell u maggies expenses

okay here set u=e^(8x) v=(e^(8x)+9) du/dx=8e^(8x) dv/dx=8e^8x dy/dx=[(e^8x+9)8e^8x-e^8x(8e^8x)]/(e^8x+9)^2 dy/dx=(8e^64x+72e^8x-8e^64x]/(e^8x+9)^2 =72e^8x/(e^8x+9)^2 check if i mad any erroe