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Questions (5)
the parametric equation of a curve are x=cos2Øand y=1+sin2Ø find dy/dx and d^2y/dx^2 at Ø=pai/6.find the relationship between
1 answer
443 views
y=3e^(2x)cos(2x-3) verify that d^2y/dx^2-4dy/dx+8y=0
plz help me i tried all i could but it become too complicated for me here
1 answer
776 views
if y=3e^(2x)cos(2x-3) verify that d^2y/dx^2-4dy/dx+8y=0
plz help me i tried all i could but it become too complicated for me here
2 answers
2,802 views
sir steve what about these i just solved it now i didnt get it
if x^2+2xy+3y^2=1 prove that (x+3y)^3d^2y/dx^2+2(x^2+2xy+3y^2)=0 i
1 answer
711 views
sir steve plz am a little confuse
(x-y)³=A(x+y) prove that (2x+y)dy/dx=x+2y if y is a function of x and x=e^t/(e^t+1) show that
4 answers
739 views
Answers (5)
okay here set u=e^(8x) v=(e^(8x)+9) du/dx=8e^(8x) dv/dx=8e^8x dy/dx=[(e^8x+9)8e^8x-e^8x(8e^8x)]/(e^8x+9)^2 dy/dx=(8e^64x+72e^8x-8e^64x]/(e^8x+9)^2 =72e^8x/(e^8x+9)^2 check if i mad any erroe
bart=2p+k=16 lisa=p+2k=11 maggie=p+k solve those 2 up there and that will tell u maggies expenses
okay i think i understand now thanks you are good
and also what happen to the orther e^t+1 becus u have x/e^t+1 and in conclusion u said x(1-x)
k i just practise that now and i got dy/dx=(3(x-y)^2-A)/(A+3(x-y)^2) how did u get dy/dx=-1 plz explain