y = 32−x^2, y = x^2; about x=4
Trying to find V by using the method of cylindrical shells.
I got 1280pi/3, but my homework says it's wrong.
I did V=∫[0,4] 2πrh dx, which got me to V=∫[0,4] 2π(4-x)(32-2x^2)dx, hence 1280pi/3. But it's wrong and I'm stuck on it.
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